![]() Question 1: Draw a square of 9 square cm. How do you get a longer belt next time?.Since its width is the smallest.īecause the entire sheet of paper is used without any wastage. For Belt 3: Perimeter = 90 cm and Area = 126 square cm.Īns. Its area = length x breadth = 42 x 3 = 126 square cm. Hence, its perimeter = 2 (length + breadth) = 2 (42 + 3) = 2 x 45 = 90 cm. When you join the strips to make a belt, the total length of the belt is 14+14+14 = 42 cm. Since the size of the rectangle is 14 cm x 9 cm, you will have 3 strips having a width of 3 cm and length of 14 cm. Its area = length x breadth = 84 x 1.5 = 126 square cm.įor Belt 2: Perimeter = 171 cm and Area = 126 square cm. When you join the strips to make a belt, the total length of the belt is 14+14+14+14+14+14 = 84 cm. Since the size of the rectangle is 14 cm x 9 cm, you will have 6 strips having a width of 1.5 cm and length of 14 cm. Its area = length x breadth = 126 x 1 = 126 square cm.įor Belt 1: Perimeter = 254 cm and Area = 126 square cm. When you join the strips to make a belt, the total length of the belt is 14+14+14+14+14+14+14+14+14 = 126 cm. Since the size of the rectangle is 14 cm x 9 cm, you will have 9 strips having a width of 1 cm and length of 14 cm. Find out the area and perimeters of each belt. You should have three belts with different widths now. Use a tape and join the strips, end to end to make a belt. Cut each one of them into thin strips of different widths of 1cm, 1.5 cm, and 3 cm. Perimeter of the rectangular sheet = length + length + breadth + breadthĪrea of the rectangular sheet = length x breadth Instead, you can calculate it as follows: Answer the following questions:īy now, you understand that to calculate the perimeter and area of a rectangle, you don’t have to use the small squares method. Take a thick sheet of paper having a length of 14 cm and width of 9 cm. The Belt Puzzle to understand Perimeter and Area of a Rectangle Now, the area of the board is 80 x 80 = 6400 square cm. Hence, the length of each side of the carom board is 320/4 = 80 cm … we divided the perimeter by 4 since the square has 4 sides. Also, we know that the perimeter of the board is 320 cm. Since the carom board is a square, all its sides are equal. You have a square carrom board whose perimeter is 320 cm. You can try placing the stamps on the rectangle and count them to cross check.Ĭheck out our detailed article on Area of a Square here. Hence, the total number of stamps that you can place is 5 x 10 = 50 stamps. Now, since the rectangle is 10 cm long and the stamp is 2 cm long, you can place 5 stamps along the length of the rectangle.Īlso, you can place 10 stamps along the width of the rectangle. This means that the length of its side is 2cm. How many stamps can you place along the length of the rectangle? The stamp is a square having an area of 4 square cm. How would you do solve this? One way is to place the stamps on the rectangle and count them. ![]() ![]() The rectangle is 10 cm long and 20 cm wide. You need to find how many such stamps you can fit in the rectangle given below: Exercise 1Ī square stamp has an area of 4 square cm. Hence, he thought that it would be simpler to multiply both sides of a rectangle or square to find its area. Similarly, he observed that in Rohini’s case it was 11cm x 3 cm = 33 square cm. He observed that the total number of squares that fit on his piece was equal to the multiplication of the measurement of both sides. However, Ram looked a little interested in the squares. Ram managed to place 30 small squares on his piece and Rohini had 33 pieces. Then, they started measuring the pieces of the dried mango slices. So, Ram and Rohini cut square pieces of paper of side 1 cm. He gave them the idea of using small squares to calculate the area. Not being able to find the answer they approached a friend – Shiv. After coming out of the shop, they started comparing who got a bigger piece? Their pieces looked like these: Ram and Rohini purchased dried mango slices from a shop. ![]()
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